3.1819 \(\int \sqrt{1-2 x} (3+5 x)^3 \, dx\)

Optimal. Leaf size=53 \[ \frac{125}{72} (1-2 x)^{9/2}-\frac{825}{56} (1-2 x)^{7/2}+\frac{363}{8} (1-2 x)^{5/2}-\frac{1331}{24} (1-2 x)^{3/2} \]

[Out]

(-1331*(1 - 2*x)^(3/2))/24 + (363*(1 - 2*x)^(5/2))/8 - (825*(1 - 2*x)^(7/2))/56 + (125*(1 - 2*x)^(9/2))/72

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Rubi [A]  time = 0.009292, antiderivative size = 53, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.059, Rules used = {43} \[ \frac{125}{72} (1-2 x)^{9/2}-\frac{825}{56} (1-2 x)^{7/2}+\frac{363}{8} (1-2 x)^{5/2}-\frac{1331}{24} (1-2 x)^{3/2} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[1 - 2*x]*(3 + 5*x)^3,x]

[Out]

(-1331*(1 - 2*x)^(3/2))/24 + (363*(1 - 2*x)^(5/2))/8 - (825*(1 - 2*x)^(7/2))/56 + (125*(1 - 2*x)^(9/2))/72

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \sqrt{1-2 x} (3+5 x)^3 \, dx &=\int \left (\frac{1331}{8} \sqrt{1-2 x}-\frac{1815}{8} (1-2 x)^{3/2}+\frac{825}{8} (1-2 x)^{5/2}-\frac{125}{8} (1-2 x)^{7/2}\right ) \, dx\\ &=-\frac{1331}{24} (1-2 x)^{3/2}+\frac{363}{8} (1-2 x)^{5/2}-\frac{825}{56} (1-2 x)^{7/2}+\frac{125}{72} (1-2 x)^{9/2}\\ \end{align*}

Mathematica [A]  time = 0.0114776, size = 28, normalized size = 0.53 \[ -\frac{1}{63} (1-2 x)^{3/2} \left (875 x^3+2400 x^2+2661 x+1454\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[1 - 2*x]*(3 + 5*x)^3,x]

[Out]

-((1 - 2*x)^(3/2)*(1454 + 2661*x + 2400*x^2 + 875*x^3))/63

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Maple [A]  time = 0.003, size = 25, normalized size = 0.5 \begin{align*} -{\frac{875\,{x}^{3}+2400\,{x}^{2}+2661\,x+1454}{63} \left ( 1-2\,x \right ) ^{{\frac{3}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3+5*x)^3*(1-2*x)^(1/2),x)

[Out]

-1/63*(875*x^3+2400*x^2+2661*x+1454)*(1-2*x)^(3/2)

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Maxima [A]  time = 1.02515, size = 50, normalized size = 0.94 \begin{align*} \frac{125}{72} \,{\left (-2 \, x + 1\right )}^{\frac{9}{2}} - \frac{825}{56} \,{\left (-2 \, x + 1\right )}^{\frac{7}{2}} + \frac{363}{8} \,{\left (-2 \, x + 1\right )}^{\frac{5}{2}} - \frac{1331}{24} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^3*(1-2*x)^(1/2),x, algorithm="maxima")

[Out]

125/72*(-2*x + 1)^(9/2) - 825/56*(-2*x + 1)^(7/2) + 363/8*(-2*x + 1)^(5/2) - 1331/24*(-2*x + 1)^(3/2)

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Fricas [A]  time = 1.55671, size = 93, normalized size = 1.75 \begin{align*} \frac{1}{63} \,{\left (1750 \, x^{4} + 3925 \, x^{3} + 2922 \, x^{2} + 247 \, x - 1454\right )} \sqrt{-2 \, x + 1} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^3*(1-2*x)^(1/2),x, algorithm="fricas")

[Out]

1/63*(1750*x^4 + 3925*x^3 + 2922*x^2 + 247*x - 1454)*sqrt(-2*x + 1)

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Sympy [B]  time = 1.767, size = 236, normalized size = 4.45 \begin{align*} \begin{cases} \frac{50 \sqrt{5} i \left (x + \frac{3}{5}\right )^{4} \sqrt{10 x - 5}}{9} - \frac{55 \sqrt{5} i \left (x + \frac{3}{5}\right )^{3} \sqrt{10 x - 5}}{63} - \frac{121 \sqrt{5} i \left (x + \frac{3}{5}\right )^{2} \sqrt{10 x - 5}}{105} - \frac{2662 \sqrt{5} i \left (x + \frac{3}{5}\right ) \sqrt{10 x - 5}}{1575} - \frac{29282 \sqrt{5} i \sqrt{10 x - 5}}{7875} & \text{for}\: \frac{10 \left |{x + \frac{3}{5}}\right |}{11} > 1 \\\frac{50 \sqrt{5} \sqrt{5 - 10 x} \left (x + \frac{3}{5}\right )^{4}}{9} - \frac{55 \sqrt{5} \sqrt{5 - 10 x} \left (x + \frac{3}{5}\right )^{3}}{63} - \frac{121 \sqrt{5} \sqrt{5 - 10 x} \left (x + \frac{3}{5}\right )^{2}}{105} - \frac{2662 \sqrt{5} \sqrt{5 - 10 x} \left (x + \frac{3}{5}\right )}{1575} - \frac{29282 \sqrt{5} \sqrt{5 - 10 x}}{7875} & \text{otherwise} \end{cases} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)**3*(1-2*x)**(1/2),x)

[Out]

Piecewise((50*sqrt(5)*I*(x + 3/5)**4*sqrt(10*x - 5)/9 - 55*sqrt(5)*I*(x + 3/5)**3*sqrt(10*x - 5)/63 - 121*sqrt
(5)*I*(x + 3/5)**2*sqrt(10*x - 5)/105 - 2662*sqrt(5)*I*(x + 3/5)*sqrt(10*x - 5)/1575 - 29282*sqrt(5)*I*sqrt(10
*x - 5)/7875, 10*Abs(x + 3/5)/11 > 1), (50*sqrt(5)*sqrt(5 - 10*x)*(x + 3/5)**4/9 - 55*sqrt(5)*sqrt(5 - 10*x)*(
x + 3/5)**3/63 - 121*sqrt(5)*sqrt(5 - 10*x)*(x + 3/5)**2/105 - 2662*sqrt(5)*sqrt(5 - 10*x)*(x + 3/5)/1575 - 29
282*sqrt(5)*sqrt(5 - 10*x)/7875, True))

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Giac [A]  time = 2.14161, size = 78, normalized size = 1.47 \begin{align*} \frac{125}{72} \,{\left (2 \, x - 1\right )}^{4} \sqrt{-2 \, x + 1} + \frac{825}{56} \,{\left (2 \, x - 1\right )}^{3} \sqrt{-2 \, x + 1} + \frac{363}{8} \,{\left (2 \, x - 1\right )}^{2} \sqrt{-2 \, x + 1} - \frac{1331}{24} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^3*(1-2*x)^(1/2),x, algorithm="giac")

[Out]

125/72*(2*x - 1)^4*sqrt(-2*x + 1) + 825/56*(2*x - 1)^3*sqrt(-2*x + 1) + 363/8*(2*x - 1)^2*sqrt(-2*x + 1) - 133
1/24*(-2*x + 1)^(3/2)